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Nathanael A. Fortune edited section_Nuclear_Schottky_effect_In__.tex
over 8 years ago
Commit id: 3d3ad84b68525ae183b4d963702e92dfae2ed92f
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where ${\mu}_0 = 4\pi \cdot 10^{-7} \textrm{ H/m}$ and the nuclear Curie constant $\lambda_N$ is given by
\begin{equation}
\label{eq:CurieConstant}
\lambda_N \frac{\lambda_N}{\mu_0} =
\mu_0 N_A I (I+1)\frac{\left({\mu}_N g_N\right)^2}{3
k_B}. k_B} \textrm{ J K / mol T^2}.
\end{equation}
where the nuclear magneton $\mu_N = \frac{h e}{4 \pi M_p c} = 5.051 10^{-27} \textrm{ J/T}$ is a factor of 1836.1 smaller than the Bohr magneton $\mu_B$. Note that in this expression, we are assuming that the zero field field splitting (ZFS) is negligible in comparison to that from the applied field $H$.