Nathanael A. Fortune edited section_Application_to_Specific_Heat__.tex  over 8 years ago

Commit id: 3452e701cfe6257a6f87b3c75e09f3b3a3b8ae6c

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\label{eq:NuclearCuContribution}  c = \alpha \left(\frac{H}{T}\right)^2 \mathrm{\ [J/K]}  \end{equation}  where $\alpha_{\textrm{Jan run}} = 1.28 \cdot 10^{-9}$ and 10^{-9}$,  $\alpha_{\textrm{July run}} = 1.60 \cdot 10^{-9}$ and $\alpha$  has units $\left[\frac{\textrm{Joules Kelvin}}{(\textrm{Tesla})^2}\right]$.