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Nathanael A. Fortune edited section_Application_to_Specific_Heat__.tex
over 8 years ago
Commit id: 3227bf0863f2c5b4cb463d98f89803fac62d5ccd
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In our Jan 2015 heat capacity run, we used a 0.40 mg sample of $\kappa$-(BEDT-TTF)$_2$Cu(NCS)$_2$. In our July 2015 run, we used a 0.50 mg sample. Assuming a molar mass of $832.98 \mathrm{g/mole}$ and 1 Cu atom per mole, the nuclear contribution to the measured heat capacity of $\kappa$-(BEDT-TTF)$_2$Cu(NCS)$_2$ is predicted to be
\begin{equation}
\label{eq:NuclearCuContribution}
C =
\alpha(H^2) T^{-2} \alpha \left(\frac{H}{T}\right)^2
\end{equation}
where $\alpha = $