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$\kappa$-(BEDT-TTF)$_2$Cu(NCS)$_2$ --- with chemical formula C$_{22}$H$_{16}$N$_{2}$S$_{18}$Cu$_{1}$ \cite{Urayama_1988} --- has a molar mass $m_{mole}$ of $832.98 \textrm{ g/mole}$.     The predominant stable isotope of hydrogen is ${}^{\ 1}_{\ 1}\textrm{H}$, which has a nuclear spin $I = 1/2$ (in units of $\hbar$) and a nuclear magnetic moment $\mu = 2.79278$ (in units of nuclear magnetons), resulting in a nuclear g-factor $g =\mu/I = 5.586$ \cite{Fuller_1976}. This can lead to a significant contribution to the magnetic field dependent nuclear specific heat at dilution refrigerator temperatures. \footnote{One way to correct for this term in H-rich organic conductors is to repeat the measurements using samples containing In  deuterated hydrogen samples --- where ${}^{\ 1}_{\ 1}\textrm{H}$ is replaced by  ${}^{\ 2}_{\ 1}\textrm{H}$. This has a 1}\textrm{H}$ -- the  nuclear spin $I = 1$ and a the  nuclear magnetic moment $\mu = 0.85742$, resulting in a much smaller nuclear g-factor $g =I/\mu = 0.857$.} 0.857$.  The two most common stable Cu isotopes are ${}^{\ 63}_{\ 29}\textrm{Cu}$ and ${}^{\ 65}_{\ 29}\textrm{Cu}$. ${}^{\ 63}_{\ 29}\textrm{Cu}$ has a nuclear spin $I = 3/2$ and a nuclear magnetic moment $\mu = 2.2228$ while ${}^{\ 65}_{\ 29}\textrm{Cu}$ has a nuclear spin $I = 3/2$ and a nuclear magnetic moment $\mu = 2.3812$ \cite{Fuller_1976}. Here, $\mu_N$ is the nuclear magneton, $g = \mu / I$ and the resulting energy splitting in applied field is $\Delta = g \mu_n H / k \textrm{ [K]}$.