Nathanael A. Fortune edited section_Application_to_Specific_Heat__.tex  over 8 years ago

Commit id: 08bb77470097b60934a8b4a83e5b2f7c0760f1db

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\alpha = m_{mole} \left( \frac{ {\lambda}_{Cu} + {\lambda}_{H} }{ {{\mu}_0} } \right)  \end{equation}  where $\alpha_{Cu} = 1.28 4.94  \cdot 10^{-9} \left[\frac{\textrm{J K}}{{\textrm{T}}^2}\right]$ and $\alpha_{Cu} = 1.60 6.18  \cdot 10^{-9} \left[\frac{\textrm{J K}}{{\textrm{T}}^2}\right]$ for the Jan 2015 and July 2015 runs, respectively.