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Stephanie Bernard edited Now_its_time_time.tex
about 8 years ago
Commit id: 45817f43d92f7c42397abc11e540b93bea288fd6
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`Colour' in astronomy is not colour like the colours of the rainbow. It is defined as the \emph{ratio of how bright a star is when viewed through two different filters}. Remember that ratio of brightnesses is the same as the difference in magnitudes (just from the usual logarithm laws). If, for example,
the magnitude of a star observed through the green filter is $V$, and its
magnitude when observed through a blue filter is $B$, then its colour
could be measured as $B-V$.
{\color{red}
\begin{itemize}
\item If
$B-V$ is large, the object is relatively
brighter in green light, compared to blue
light. light, then its $B-V$ will be a positive number. Astronomers would say it had a ``red'' colour, even though it is actually the blue and green light which is being considered.
\item If
the object is brighter in blue light than green, its $B-V$
was negative, it will be negative. It would
then have a ``blue'' colour.
\end{itemize}
}
For all the objects in your CCD frames, compute colours, and plot
these colours against one of the absolute magnitudes (eg. $M_V$
against $B-V$). This is an HR diagram!