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Eugeniu Plamadeala edited untitled.tex
about 9 years ago
Commit id: fdd6ec82a639ddfc990b4d313d81d145be02ac6c
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$$ \left[ \phi_L, \partial_x \phi_L \right] = i 2\pi \delta(x-y) $$
This matches eqn 1.17 of Mike's notes under the identification $\phi_I \equiv \phi^R_I,\phi_{N+I} \equiv \phi^L_I$. Moreover, it is also true that
$$ [\rho_R, e^{i \phi_R^{(G)} ] = [ \frac{1}{2\pi}\partial_x \phi_R^{(G)}, e^{i \phi_R^{(G)}} ]= \delta(x-y)e^{i\phi_R^{(G)}} $$
$$ [\rho_{R,I}, e^{i \phi_I}] = [ \frac{-1}{2\pi} \partial_x \phi^R_I, e^{i \phi^R_I} ] = \delta(x-y) e^{i\phi^R_I(y)} $$