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Eugeniu Plamadeala edited untitled.tex
about 9 years ago
Commit id: 41933b80be51257171b0c2de16acf85d90e04932
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$$ P = \frac{1}{4\pi} \sum_I k_{F,I} \left(\partial_x \phi_I - \partial_x \phi_{N+I} \right) + \frac{1}{4\pi} \sum_I \left( (\partial_x \phi_I)^2 - (\partial_x \phi_{N+I})^2 \right) $$
Fermion density. Giamarchi claims (eq 2.55), for a non-chiral boson, $ \rho_R(x) + \rho_L(x) = \frac{-1}{\pi}\partial_x \phi $. In addition
$\phi_R $\phi_R^{(G))} = K\theta - \phi,
\phi_L \phi_L^{(G))} = K \theta + \phi$. His final action for the chiral bosons looks like (C.12 upon above field redefinition)
$$ -S_G = \frac{1}{4\pi K} \int d\tau dx \left[ i \partial_\tau \phi_R \partial_x \phi_R - i \partial_\tau \phi_L \partial_x \phi_L - ... \right]$$
It looks just like the perfect metal action, so I conclude that (dropping the factor of K):