Paul Cuffe edited Zero Row Summation of Yggm.tex  about 9 years ago

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\sum_{j=1}^mg_{ij}=\sum_{k=1}^n[(-1+\sum_{j=1}^mc_{kj})b_{ik}].  \end{equation}  As the authors have shown in \cite{2015arXiv150308652D} \cite{FLG}  [9], if $det(Y_{LL})\neq 0$, then every row of $F_{LG}$ sums to one, i.e. $\sum_{j=1}^mc_{kj}=1$, $\forall k=1,2,...,n$. \\Thus, from \eqref{eq:eq5}, $\sum_{j=1}^mg_{ij}=0$, and so every row of $Y_{GGM}$ sums to zero.  Similarly, if $det(Y_{LL})=0$, then every row of $F_{LG}$ sums approximately to one, i.e. $\sum_{j=1}^mc_{kj}\cong 1$, $\forall k=1,2,...,n$   \\Thus, from \eqref{eq:eq5}, $\sum_{j=1}^mg_{ij}\cong 0$, and so every row of $Y_{GGM}$ sums approximately to zero.