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\subsection{Problem 3}  With a $s$ factor or 3.5 the memory performance increases to 50\% of the new latency or $CPU_time$. Using absolute execution times, Amdahl's law is in terms of $L_{new}$, the execution time after an improvement; , $L_{memory}$ the execution time affected by the improvement; $s$, how many times faster the improved part runs, or its speedup; and $L_{unaffected}, $L_{unaffected}$,  the execution time unaffected by the improvement. In these terms, Amdahl's Law states that: \begin{displaymath}{L_{new}=\frac{L_{memory}}{s} + L_{unaffected}}\end{displaymath} If we assume that $L_{new} = 100$ then based on the given that the new memory latency is 50\%, then that would imply that $L_{unaffected} = 50$. Using these numbers in the Amdahl's law we get the following:  \begin{displaymath}{100=\frac{L_{memory}}{3.5} + 50}\end{displaymath}  Solving for $L_{memory}$ would result in it being 175. This will then give us a total $L_{old} = 175 + 50 = 224$. Now we can calculate the percentage that $L_{memory}$ is of the original latency:  $\frac{175}{225) * 100 = 77.77\%$