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Kunal Marwaha edited Control Theory.tex
almost 9 years ago
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Our observation $P_3(t)$ can be interpreted as $\v{y}(t)$ as shown above. In particular, $C(t) = C = \begin{matrix}(0 & 0 & 0 & F)\end{matrix}$ and $D(t) = \v{0}$. Can the time dependence within $H(t)$ be modeled as input $\v{u}(t)$ to the system? In general, $H(t) = H_0 + E(t) \cdot \mu$.
Let us define superoperators
$A_0, A_1$ $M_0, M_1$ such that
$A(t) $M(t) = A_0 + E(t) \cdot
A_1$. M_1$. By linearity of the commutator, applying
$A_0$ $M_0$ (in operator form) can behave as
$A_0 $M_0 \cdot = \frac{-i}{\hbar}[H_0,\cdot]$, and applying
$A_1$ $M_1$ (in operator form) can behave as
$A_1 $M_1 \cdot = \frac{-i}{\hbar}[\mu,\cdot]$.
Now, all matrices are time-independent, but there remains coupling between $\v{x}(t)$ and $E(t)$. In particular, we have the evolution equation:
\[ \dot{\v{x}}(t) = \left( \begin{array}{cccc}
0 & 0 & 0 & 0 \\
A_0 M_0 & 0 & 0 & 0 \\
0 &
A_0 M_0 & 0 & 0 \\
0 & 0 &
A_0 M_0 & 0 \\
\end{array} \right) \v{x}(t) + \left( \begin{array}{cccc}
0 & 0 & 0 & 0 \\
A_1 M_1 & 0 & 0 & 0 \\
0 &
A_1 M_1 & 0 & 0 \\
0 & 0 &
A_1 M_1 & 0 \\
\end{array} \right) \v{x}(t) E(t) \]
Bilinear system theory may be well-equipped to handle this coupling.