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Hans Moritz Günther edited develop_ode.tex
over 10 years ago
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...
For the given mass loss rate $\dot M$ of the stellar wind, the wind density at any distance $r=\sqrt{z^2+\omega^2}$ from the central star is
\begin{equation}\label{eqn:rho}
\rho(r) = \frac{\dot M}{4 \pi r^2
v_{\inf}}\ v_{\infty}}\ .
\end{equation}
Figure~\ref{fig:sketch} shows that $v_0$ depends on the position of the shock:
\begin{equation}
\label{eqn:v0}v_0 =
v_{\inf} v_{\infty} \sin \psi
\end{equation}
with
\begin{equation}\label{eqn:angle}
...
\end{equation}
Inserting equation~\ref{eqn:rho} to \ref{eqn:deriv} into eqn.~\ref{eqn:4}, we arrive at an ordinary differential equation, that describes the functional form of the shape of the shock front:
\begin{equation}
P(z) = \frac{3}{4}\rho_0v_0^2 = \frac{3}{4} \frac{\dot{M}}{4\pi
v_{\inf}(z^2+\omega^2)} v_{\inf}^2 v_{\infty}(z^2+\omega^2)} v_{\infty}^2 \sin^2(\psi)
\end{equation}
This equation can be simplified to
\begin{equation}\label{eqn:ode}
...
\end{equation}
with
\begin{equation}
c = \frac{16\pi P(z)}{3 \dot{M}
v_{\inf}}\ v_{\infty}}\ .
\end{equation}