Nathan Sanders edited Problem 1.tex  about 11 years ago

Commit id: 8f16117049021db540d8a0413d874fa5d619c767

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b=\frac{2e^2}{m_e v^2}\sim1\times10^{-7}~\rm{cm}  \end{equation}  \noindent which corresponds to $l=3\times10^{13}~\rm{cm}$ and a timescale $\tau=l/v\sim4\times10^5~\rm{s}\sim5~\rm{days}\\sim0.01~\rm{years}$. $\tau=l/v\sim4\times10^5~\rm{s}\sim5~\rm{days}\sim0.01~\rm{years}$.  \subsection{Part b}