Nathan Sanders edited Problem 1.tex  about 11 years ago

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F_G=\frac{Gm_em_p}{r^2}  \end{equation}  The ratio is therefore:  \begin{equation}  \frac{F)c}{F_G}=\frac{e^2}{Gm_em_p}\sim2.3\times10^{39}  \end{equation}  The  \subsection{Part c}