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Nathan Sanders edited Problem 1.tex
about 11 years ago
Commit id: 306cd7ae692397c9caad5987d2e7d148d1305c5e
deletions | additions
diff --git a/Problem 1.tex b/Problem 1.tex
index 5603085..4230128 100644
--- a/Problem 1.tex
+++ b/Problem 1.tex
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F_G=\frac{Gm_em_p}{r^2}
\end{equation}
The ratio is therefore:
\begin{equation}
\frac{F)c}{F_G}=\frac{e^2}{Gm_em_p}\sim2.3\times10^{39}
\end{equation}
The
\subsection{Part c}