Nathan Sanders edited Problem 1.tex  about 11 years ago

Commit id: 005feca576af3c35114bd2f8886b92dd094ccf7e

deletions | additions      

       

b=\frac{2e^2}{m_e v^2}\sim1\times10^{-7}~\rm{cm}  \end{align}  \noindent which corresponds to a mean free path of $l=3\times10^{-13}~\rm{cm}$. The timescale is then $\boxed{\tau=l/v\sim4\times10^5~\rm{s}\sim5~\rm{days}\sim0.01~\rm{yrs}$.  \subsection{Part b}   \subsection{Part c}