Statistics HW 4
c)No I only got 2 heads
\(7/4, -10\%\) cant be real probabilities for \(7/4\) is larger than one and we cant have negative probabilities.
Were looking at the total numbers for Democrat or Republican, and since this is an or questions we add \((689+469)/1858=62.3\%\)
Following the guided excersice\(P(Liberal)=530/1858=28.5\%\)
They arent mutually exclusive because you can see that there are people who are both liberal and democrat.
\(P(Lib and Dem)=(306)/1858=16.5\%\)
If we dont subtract away the probability of people being democrat and liberal from that equation, you will be over counting.
\(P(Lib or Dem)=(530+689-306)/1858=49.1\%\)
a)\(P(Odd or less than 3)=3/6+2/6-1/6=4/6=66.7\%\)
b)\(P(Odd or less than 2)=3/6+1/6-1/6=50\%\)
e)1 because they are compliments.
d)a and c are complementary.16 or more mistakes mean 16 up to 30. 15 or fewer all values from 0 up to 15. If you add these together you get the whole experiment.
c)The highest percent is with liberal democrats.
Follow the guided exercise
since the two probabilities are equal we can say these are independent.