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  • Statistics HW 4

    Christopher Spencer
    UCID: 404-148-996
    Assignment #4
    Discussion 2B

    Chapter 5

    5.1

    a)2,6,4,2,7,4,0,6,5,0
    b)T,T,T,T,H, T,T,T,H,T
    c)No I only got 2 heads

    5.10

    \(7/4, -10\%\) cant be real probabilities for \(7/4\) is larger than one and we cant have negative probabilities.

    5.15

    a)\(1/16\)
    b)\(4/16=1/4\)
    c)\(6/16=3/8\)
    d)\(4/16=1/4\)
    e)\(1/16\)

    5.21

    \(104/1858=5.6\%\)

    5.22

    \(26/1858=1.4\%\)

    5.23

    Were looking at the total numbers for Democrat or Republican, and since this is an or questions we add \((689+469)/1858=62.3\%\)

    5.24

    \((593+530/1858=60.4\%\)

    5.25

    Following the guided excersice\(P(Liberal)=530/1858=28.5\%\)
    \(P(Democrat)=689/1858=37.1\%\)
    They arent mutually exclusive because you can see that there are people who are both liberal and democrat.
    \(P(Lib and Dem)=(306)/1858=16.5\%\)
    If we dont subtract away the probability of people being democrat and liberal from that equation, you will be over counting.
    \(P(Lib or Dem)=(530+689-306)/1858=49.1\%\)

    5.33

    a)\(P(Odd or less than 3)=3/6+2/6-1/6=4/6=66.7\%\)
    b)\(P(Odd or less than 2)=3/6+1/6-1/6=50\%\)

    5.40

    a)\(15/50= 30\%\)
    b)\(35/50=70\%\)
    c)30/50=60%\(\\ d)20/50=40\%\)
    e)1 because they are compliments.

    5.44

    a)\(1-0.23-0.41=0.36\)
    b)\(0.41+0.36=0.77\)
    c)\(0.41+0.23=0.64\)
    d)a and c are complementary.16 or more mistakes mean 16 up to 30. 15 or fewer all values from 0 up to 15. If you add these together you get the whole experiment.

    5.47

    a)\(306/530=57.7\%\)
    b)\(104/593=17.53\%\)
    c)The highest percent is with liberal democrats.

    5.57

    Follow the guided exercise

    \(P(Right)=60/100=60\%\)
    \(18/30=60\%\)
    since the two probabilities are equal we can say these are independent.

    5.59

    a)