Statistics HW 4

Christopher Spencer
UCID: 404-148-996
Assignment #4
Discussion 2B

Chapter 5

5.1

a)2,6,4,2,7,4,0,6,5,0
b)T,T,T,T,H, T,T,T,H,T
c)No I only got 2 heads

5.10

\(7/4, -10\%\) cant be real probabilities for \(7/4\) is larger than one and we cant have negative probabilities.

5.15

a)\(1/16\)
b)\(4/16=1/4\)
c)\(6/16=3/8\)
d)\(4/16=1/4\)
e)\(1/16\)

5.21

\(104/1858=5.6\%\)

5.22

\(26/1858=1.4\%\)

5.23

Were looking at the total numbers for Democrat or Republican, and since this is an or questions we add \((689+469)/1858=62.3\%\)

5.24

\((593+530/1858=60.4\%\)

5.25

Following the guided excersice\(P(Liberal)=530/1858=28.5\%\)
\(P(Democrat)=689/1858=37.1\%\)
They arent mutually exclusive because you can see that there are people who are both liberal and democrat.
\(P(Lib and Dem)=(306)/1858=16.5\%\)
If we dont subtract away the probability of people being democrat and liberal from that equation, you will be over counting.
\(P(Lib or Dem)=(530+689-306)/1858=49.1\%\)

5.33

a)\(P(Odd or less than 3)=3/6+2/6-1/6=4/6=66.7\%\)
b)\(P(Odd or less than 2)=3/6+1/6-1/6=50\%\)

5.40

a)\(15/50= 30\%\)
b)\(35/50=70\%\)
c)30/50=60%\(\\ d)20/50=40\%\)
e)1 because they are compliments.

5.44

a)\(1-0.23-0.41=0.36\)
b)\(0.41+0.36=0.77\)
c)\(0.41+0.23=0.64\)
d)a and c are complementary.16 or more mistakes mean 16 up to 30. 15 or fewer all values from 0 up to 15. If you add these together you get the whole experiment.

5.47

a)\(306/530=57.7\%\)
b)\(104/593=17.53\%\)
c)The highest percent is with liberal democrats.

5.57

Follow the guided exercise

\(P(Right)=60/100=60\%\)
\(18/30=60\%\)
since the two probabilities are equal we can say these are independent.

5.59

a)