ROUGH DRAFT authorea.com/5280
Main Data History
Export
Show Index Toggle 0 comments
  •  Quick Edit
  • Math 132 Notes

    Lectures and Notes

    week 8 notes review

    Taylors Theorem says if \(f\) is analytic on \(\{z:|z-z_0|<r\}\) and continuous on the domain that includes the boundary, then \(f(z)=\sum_{n=0}^{\infty}f^{(n)}(z_0)\frac{(z-z_0)^n}{n!}\) and this series converges absolutely. Cauchys inequality says that if is analytic in \(\{z\in\mathbb{c}:|z-z_0|<r\}\) and \(|f(z)|\leq c\) in the disk then the function converges absolutely.

    Isolated Singularities

    A function which is analytic on the punctured disk \(\{z\in\mathbb{c}:0<|z-z_0|<r\}\) has an isolated singularity at \(z_0\).There are three examples of isolated singularities.

    1. removable singularity: where \(f(z)\) is bounded for some \(r>0\) on \(\{0<|z-z_0|<r\}\), remains bounded as \(z\rightarrow z_0\)

    2. poles: where \(\lim_{z\to z_0}|f(z)|=\infty\)

    3. essential singularity: when 1 or 2 dont apply

    lemma: if \(f\) has a removable singularity at \(z_0\) then the \(\lim_{z\to z_0} f(z)\) exists and extends \(f\) to an analytic function at \(z_0\).

    \(0 < |z| < 2pi\)

    [Someone else is editing this]

    You are editing this file