PROBLEMA 3

What is the magnitude of the electric force of  attraction between  an iron nucleus  (= + 26e) and its  innermost electron if the distance between them is 1.5 X 10-12 m?
\(f_{31}=k\ \frac{Q_3\ Q_1}{r_{31}}=\left(9x10^9\ \frac{nm^2}{c^2}\right)\left(\frac{\left(26\left(-1.602x10^{-19}c\right)\right)\left(-1.602x10^{-19}c\right)}{\left(1.5x10^{-12}m\right)^2}\right)=2.67n\)