et, consectetur adipiscing elit \citet{28439448}. Cras egestas auctor molestie. In hac habitasse platea dictumst. Duis turpis tellus, scelerisque sit amet lectus ut, ultricies cursus enim. Integer fringilla a elit at fringilla. Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nulla congue consequat consectetur. Duis ac mi ultricies, mollis ipsum nec, porta est. \(_{12}^4\mathbf{C}_2^5\) \(\)\(\sqrt{2}+a\)\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)