1.- Ax +Bx
2.- Ay -w= 0
Ay= w
3.- -xw +Bx (4ft)= 0
-2 r/\(\Pi\)( 0.5 lb/ft)\(\Pi\) + Bx (4ft) =0
-2\(r^2\)(0.5 lb/ ft) + 4 ft Bx= 0
4ft Bx= 2 \(r^2\) ( 0.5 lb/ft)
Bx= 2\(r^2\)/4 ft (0.5 lb/ ft) =[ 2(4ft) / (4ft) ] (0.5 lb) = 1 lb