3.- Dados los siguientes vectores: a=4i^-3j^+k^ y b=-i^+j^+4k^Calcule (a . b) y (a xb)

(a.b)= AxBx + AyBy + AzBz
Ax=4 Ay= -3 Az=1 Bx= -1 By=1 Bz= 4
(a.b)= (4)(-1) + (-3)(1) + (1)(4) =-4 -3 +4 = -3
A y B =-3+ + (-3)(1) + (1)(4) =-4 -3 +4 = -3
*El producto cruz seria ( a xb ) = i( AyBz - AzBy ) - j( AxBz - AzBx ) + k(AxBy - AyBx )
(a xb) =i [ (-3)(4) -(1)(1)] - j[(4)(4) - (1)(-1)] - k[(4)(4) - (1)(-1)] = i[-12 - 1] - j[ 16+1] + k[4-3] = -13i -17j +k