Consider the tow truck below. If the tensional force in the cable is 1000 N and if the cable makes a 60-degree angle with the horizontal, then what is the vertical component of force that lifts the car off the ground?
Datos
\(F_x=1000N\)
\(\theta=60\)
Fórmula
\(F_y=F\ sen\ \theta\)
Desarrollo
\(F_y=866.025N\)