FY = F SEN \(\theta\) = F SEN 60º
   =(1000)SEN 60º
=800N
FX=F COS60=(1000)COS 60º
=500
1 Problem 4. After its most recent delivery, the infamous stork announces the good news. If the sign has a mass of 10 kg, then what is the tensional force in each cable? Use trigonometric functions and a sketch to assist in the solution.
W= (10KG) (9.81)M/1"= 98.1
SOLUCION:                               EN 2D
TX: T COS \(\theta\)                                       \(\Sigma\)FX=0
TY:T SEN \(\theta\)                                        \(\Sigma\) FY=0
\(\Sigma\)FX
TX-TY
\(\Sigma\)FY
TY+TY+W=0
TSH0+TSH0-98.1N
T=98.1N/25=     98.1N/25H0= 56.63