Resultados y discusión
1mg cos(30°) i +mg sin (30°)+2mg cos (80°)+2mg sin (80°)
mg(cos30° + 2mgcos(80°)j + mg(sen30° + 2 sen 80°)i(0.866 +2 (0.173)j
10.5+2(0.984)i
1.213+2.468=3.681
\(\)\(mg=\sqrt{3.631}\)
\(mg=1.91\)
\(\theta=\tan^{-1}\left(\frac{sen30°+2\ sen80°}{\cos\ 30°\ +\ 2\cos\ 80°}\right)=63.8°mg+180=343.83°\)