fix = 1 cos 45° 
fiy = 1 sin 45°
Fx = 2 cos 115°
Fy = 2 sin 115°
F1= 1 cos 45° + 1 sin 45°= mg(cos 45° + sin 45°)
F2= 2 cos 115° + 2 sin 115° = 2mg (cos 115° + sin 115°)
\(\left|\vec{F}\right|\ =m\sqrt{\left(1\cos45°+2\cos115°\right)}^21\left(1\sin45°+2\sin45°\right)^2=2.52\)
\(\theta\tan^{_{-1}}\left(\frac{\sin45°+2\sin115°}{\cos45°+2\cos115°}\right)\ =-86.86\)
\(\theta=-86.86\)