Ahora calculamos el momento para F1:
\(i\ \left(5\right)\left(75\right)-\left(-120\right)\left(3\right)-j\ \left(4\right)\left(75\right)-\ \left(100\right)\left(3\right)+k\ \left(4\right)\left(-120\right)-\left(100\right)\left(5\right)=\ 735\ i\ -980\ k\)El momento de F2 está dado por:
\(i\ \left(5\right)\left(100\right)-\left(250\right)\left(3\right)-j\ \left(4\right)\left(100\right)-\left(-200\right)\left(3\right)+k\ \left(4\right)\left(250\right)-\left(-200\right)\left(5\right)=\ -250\ i-1000\ j+2000\ k\)
\(\vec{M_0}=\vec{M_1}+\vec{M_2}\)
\(\vec{M_0}=\ 485\ i-1000\ j\ +1020\ k\)
Problema 2.