\(\Sigma Fy:\)
\(N-500Sin\theta-w=0\)
\(N=500\left(\frac{3}{5}\right)+\ 98.1N\)
\(N=398.1\ N\)
Ahora del   \(\Sigma Fx:\)
\(500Cos\theta-300=ma\)
\(400N-300N=ma\)
\(10m\)/\(s^2\)\(=a\)
\(a=\frac{du}{dt}\)
\(U=u+at\)
\(U=at\)
\(U=20m\)/s